Answer to Question #172488 in Physics for Jeet

Question #172488

Find the force between two point charges 5uc and 10uc separated by a distance of 0.2m in air


1
Expert's answer
2021-03-18T14:04:09-0400

The force between two point charges is Coulomb's force:


F=kq1q2r2F = k\dfrac{|q_1||q_2|}{r^2}

where q1=5μC=5×106C, q2=10μC=10×106Cq_1 = 5\mu C = 5\times 10^{-6}C, \space q_2 = 10\mu C = 10\times 10^{-6}C are point charges, k=9×109Nm2/C2k = 9\times 10^9 N\cdot m^2/C^2 is the Coulomb's constant, and r=0.2mr= 0.2m is the distance between the charges. Substituting these numbers, obtain:


F=9×1095×10610×1060.22=11.25NF = 9\times 10^{9}\dfrac{|5\times 10^{-6}||10\times 10^{-6}|}{0.2^2} =11.25N

Answer. 11.25 N.


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