Answer to Question #172488 in Physics for Jeet

Question

Find the force between two point charges 5uc and 10uc separated by a distance of 0.2m in air

Answer 1

The force between two point charges is Coulomb's force:

$$F = k\dfrac{|q_1||q_2|}{r^2}$$

where $q_1 = 5\mu C = 5\times 10^{-6}C, \space q_2 = 10\mu C = 10\times 10^{-6}C$ are point charges, $k = 9\times 10^9 N\cdot m^2/C^2$ is the Coulomb's constant, and $r= 0.2m$ is the distance between the charges. Substituting these numbers, obtain:

$$F = 9\times 10^{9}\dfrac{|5\times 10^{-6}||10\times 10^{-6}|}{0.2^2} =11.25N$$

Answer. 11.25 N.