Answer to Question #172486 in Physics for Aaryan

Question

Find the electric flux through area of 2m^2 electric field of 200v/m. The angle between electric field and normal to area is 60°.

Answer 1

By definition, the flux of the constant field throug some area is:

$$\Phi =ES\cos \theta$$

where $E = 200V/m$ is the electric field, $S = 2m^2$ is the area, and $\theta = 60\degree$ is the angle between electric field and normal to area. Thus, obtain:

$$\Phi = 200\cdot 2\cdot \cos 60\degree = 200V\cdot m$$

Answer. 200 V*m.