Answer to Question #172486 in Physics for Aaryan

Question #172486

Find the electric flux through area of 2m^2 electric field of 200v/m. The angle between electric field and normal to area is 60°.


1
Expert's answer
2021-03-18T14:04:14-0400

By definition, the flux of the constant field throug some area is:


Φ=EScosθ\Phi =ES\cos \theta

where E=200V/mE = 200V/m is the electric field, S=2m2S = 2m^2 is the area, and θ=60°\theta = 60\degree is the angle between electric field and normal to area. Thus, obtain:


Φ=2002cos60°=200Vm\Phi = 200\cdot 2\cdot \cos 60\degree = 200V\cdot m

Answer. 200 V*m.


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