Answer to Question #172441 in Physics for Ashley

Question

The drawing shows a wire composed of three segments, AB, BC, and CD. There is a current of I = 2.1 A in the wire. There is also a magnetic field B (magnitude = 0.26 T) that is the same everywhere and points in the direction of +z axis. The lengths of the wire segments are L_AB = 1.0 m, L_BC = 0.5 m, and L_CD = 0.5 m. Find the magnitude of the force that acts on each segment.

Answer 1

$$F_{AB} = ILB\sin θ\\= (2.1)(1.0)(0.26)\sin 90=0.546\ N\\ F_{BC} = ILB\sin θ\\= (2.1)(0.5)(0.26)\sin 90=0.273\ N\\ F_{CD} = ILB\sin θ\\= (2.1)(0.5)(0.26)\sin 0=0\ N\\$$