Answer to Question #172428 in Physics for emmanuel

Question

a stone is thrown straight upward with a speed of 20m/s. it is caught on its way down at a point 5.0m above where it was thrown

Answer 1

$$v^2=u^2+2gh\\v^2=20^2+2(9.8)(5)\\v=22.3\frac{m}{s}$$