Answer to Question #172428 in Physics for emmanuel

Question #172428

a stone is thrown straight upward with a speed of 20m/s. it is caught on its way down at a point 5.0m above where it was thrown

Expert's answer

"v^2=u^2+2gh\\\\v^2=20^2+2(9.8)(5)\\\\v=22.3\\frac{m}{s}"

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