Question #172301

The car is moving at a speed of 7 m / s. At a certain point, the driver applies the brakes, after which the car moves another 1.5 m before stopping completely. Assuming the car is moving at a speed of 14 m / s, determine the path it would take after the driver starts braking. Assume that the braking forces are equal in both cases.


Expert's answer

Let's first find the deceleration of the car:


v2=v02+2ad,v^2=v_0^2+2ad,a=v2v022d=0(7 ms)221.5 m=16.3 ms2.a=\dfrac{v^2-v_0^2}{2d}=\dfrac{0-(7\ \dfrac{m}{s})^2}{2\cdot1.5\ m}=-16.3\ \dfrac{m}{s^2}.

Finally, we can determine the path it would take after the driver starts braking:


d=0(14 ms)22(16.3 ms2)=6.0 m.d=\dfrac{0-(14\ \dfrac{m}{s})^2}{2\cdot(-16.3\ \dfrac{m}{s^2})}=6.0\ m.
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