A ball thrown vertically upward has a speed of 5.0 m/s at a height of 3.0 m, the mass of the ball is 1.2 kg. Find its mechanical energy.
E=KE+PE=mv22+mgh=1.2⋅522+1.2⋅9.8⋅3=50.28 (J)E=KE+PE=\frac{mv^2}{2}+mgh=\frac{1.2\cdot 5^2}{2}+1.2\cdot 9.8\cdot 3=50.28\ (J)E=KE+PE=2mv2+mgh=21.2⋅52+1.2⋅9.8⋅3=50.28 (J) . Answer
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