Answer to Question #171555 in Physics for EUGINE HAWEZA

Question #171555

A body moving at 12 m/s accelerates to a velocity of 18 m/s</span>. If it covers a distance of 331 m during this time, what is the acceleration?

Expert's answer

"a=\\dfrac{v_f^2-v_i^2}{2d},""a=\\dfrac{(18\\ \\dfrac{m}{s})^2-(12\\ \\dfrac{m}{s})^2}{2\\cdot331\\ m}=0.27\\ \\dfrac{m}{s^2}."

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