Answer to Question #171555 in Physics for EUGINE HAWEZA

Question

A body moving at 12 m/s accelerates to a velocity of 18 m/s</span>. If it covers a distance of 331 m during this time, what is the acceleration?  

Answer 1

$$a=\dfrac{v_f^2-v_i^2}{2d},$$ $$a=\dfrac{(18\ \dfrac{m}{s})^2-(12\ \dfrac{m}{s})^2}{2\cdot331\ m}=0.27\ \dfrac{m}{s^2}.$$