Question #171528

  How much work is done when a force of 4000N moves its point of application 0.5m in the direction of the force?


1
Expert's answer
2021-03-14T19:12:55-0400
W=Fd=4000 N⋅0.5 m=2000 J.W=Fd=4000\ N\cdot0.5\ m=2000\ J.

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