Question #171311

12,500j of heat is absorbed by 2kg of lead. What is the temperature rise. CC=130jkg^-1k^-1


1
Expert's answer
2021-03-14T19:13:59-0400
Q=mcΔT12500=(2)(130)ΔTΔT=48 KQ=mc\Delta T\\12500=(2)(130)\Delta T\\\Delta T=48\ K


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