Question #171191

answer the problems using GRESA method:


1. A 53kg skateboarder pushes on the ground with -351N of force to set himself moving. How fast will the skateboarder accelerate?


2. A responsible driver, driving at a rate of 15m/s, sees the traffic light red. She presses on the brakes and after 3.20s, comes to a stop. The mass is 5400 g. How much force was exerted on the car?


1
Expert's answer
2021-03-14T19:14:28-0400

1) Given:

m=53 kg,F=351 N.m=53\ kg, F=351\ N.

Required:

Acceleration of the skateboarder.

Equation:

F=ma.F=ma.

Solution:

a=Fm=351 N53 kg=6.62 ms2.a=\dfrac{F}{m}=\dfrac{351\ N}{53\ kg}=6.62\ \dfrac{m}{s^2}.

Answer:

a=6.62 ms2.a=6.62\ \dfrac{m}{s^2}.


2) Given:

vi=3.2 ms,vf=0,t=3.2 s,m=5.4 kg.v_i=3.2\ \dfrac{m}{s}, v_f=0, t=3.2\ s, m=5.4\ kg.

Required:

Force exerted on the car.

Equation:

FΔt=m(vfvi).F\Delta t=m(v_f-v_i).

Solution:

F=m(vfvi)Δt,F=\dfrac{m(v_f-v_i)}{\Delta t},F=5.4 kg(015 ms)3.2 s=25.31 N.F=\dfrac{5.4\ kg\cdot(0-15\ \dfrac{m}{s})}{3.2\ s}=-25.31\ N.

Answer:

F=25.31 N.F=-25.31\ N.


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