Consider a particle of charge Q, moving perpendicular to a magnetic field of flux density B with a velocity v. Show that it will be deflected in a circular path, radius r, where:
r=p/BQ and p is the momentum of the charged particle.
"F=ma\\to qvB=m\\frac{v^2}{r}\\to qB=\\frac{mv}{r}\\to r=\\frac{mv}{qB}=\\frac{p}{qB}"
So, "r=\\frac{p}{qB}" . Answer
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