river accelerates a 200 kg motorcycle which results in a force being exerted that speeds up the motorcycle from 15m/s to 45m/s over a time interval of 13s.
The force acting on the motorcycle
F=ma=mv−v0t=200⋅45−1513≈462 (N)F=ma=m\frac{v-v_0}{t}=200\cdot\frac{45-15}{13}\approx462\ (N)F=ma=mtv−v0=200⋅1345−15≈462 (N) . Answer
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