Question

A spring 20cm long is stretched to 25cm by a load of 50N. What will be its length when stretched by 100N assuming that the elastic limit is not reached

Answer 1

$\Delta x=0.25-0.20=0.05\ (m)$

$F=k\Delta x\to k=F/\Delta x=50/0.05=1000\ (N/m)$

$\Delta x_1=F_1/k=100/1000=0.1\ (m)$

$x_1=0.2+0.1=0.3\ (m)$ . Answer