Question

A force of 10N acts on a body of mass 2kg for 0.5s. What is the increase in momentum?

Answer 1

According to the second Newton's law, the increase in momentum is:

$$\Delta P = F\Delta t$$

where $F = 10N$ is the average force that acts during the time $\Delta t = 0.5s$. Thus, obtain:

$$\Delta P = 10N\cdot 0.5s = 5 \space kg\cdot m/s$$

Answer. $5 \space kg\cdot m/s$.