Answer to Question #169644 in Physics for nasia

Question

A mercury drop of radius 1 mm is sprayed into 10^3

drops of equal sizes. Compute

the energy expended. Surface tension of mercury = 3.5 × 10^−2 N/m.

Answer 1

$$\Delta E=4\pi r^2(n^{\frac{1}{3}}-1)T\\\Delta E=4\pi (0.001)^2(1000^{\frac{1}{3}}-1)0.035=4\cdot10^{-6}\ J$$