Answer to Question #169644 in Physics for nasia

Question #169644

A mercury drop of radius 1 mm is sprayed into 10^3

drops of equal sizes. Compute

the energy expended. Surface tension of mercury = 3.5 × 10^−2 N/m.

Expert's answer

"\\Delta E=4\\pi r^2(n^{\\frac{1}{3}}-1)T\\\\\\Delta E=4\\pi (0.001)^2(1000^{\\frac{1}{3}}-1)0.035=4\\cdot10^{-6}\\ J"

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