(a) Let's use the law of continuity:
v1A1=v2A2,v2=A2v1A1=πr22πr12v1,v2=π⋅(0.005 m)2π⋅(0.01 m)2⋅1.5 sm=6.0 sm.(b) We can find the pressure from the Bernoulli's equation:
P1+ρgh1+21ρv12=P2+ρgh2+21ρv22,P2=P1−ρg(h2−h1)−21ρ(v22−v12),P2=4.0⋅105 Pa−1000 m3kg⋅9.8 s2m⋅(5 m−0)−21⋅1000 m3kg⋅((6 sm)2−(1.5 sm)2)=3.3⋅105 Pa.
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