A vertical storage tank has 2.5 m of heavy fuel oil (p=0.94g cm3) Floating on 0.5 m of water (p=1.0 g cm3). What is the pressure at the bottom of the tank due to the liquid in it?
p=p1+p2=ρ1gh1+ρ2gh2=p=p_1+p_2=\rho_1gh_1+\rho_2gh_2=p=p1+p2=ρ1gh1+ρ2gh2=
=940⋅9.8⋅2.5+1000⋅9.8⋅0.5=27930 (Pa)=940\cdot9.8\cdot2.5+1000\cdot9.8\cdot0.5=27930\ (Pa)=940⋅9.8⋅2.5+1000⋅9.8⋅0.5=27930 (Pa) .Answer
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