Answer to Question #168476 in Physics for Maria

Question

GO TO THIS LINK:

https://phet.colorado.edu/sims/html/projectile-motion/latest/projectile-motion_en.html

SOLVE RANGE, TIME, MAX HEIGHT AND FINAL SPEED/VELOCITY BY THE GIVEN BELOW.

CANON HEIGHT CANON ANGLE INITIAL VELOCITY

 0 meters 0⁰ 15 m/s

0 meters 45⁰ 15 m/s

0 meters 70⁰ 15 m/s

15 METERS -5⁰ 15 m/s

15 METERS 0⁰ 15 m/s

15 METERS 45⁰ 15 m/s

15 METERS 70⁰ 15 m/s

THANKS. HELP ME WITH THIS ONE WITH SOLUTION

Answer 1

a)

$$R=\frac{15^2\sin{0}}{9.8}=0\ m\\ t=2\frac{15\cos{0}}{9.8}=3.1\ s\\ h=\frac{15^2\cos^2{0}}{2\cdot9.8}=11.5\ m\\v=15\frac{m}{s}$$

b)

$$R=\frac{15^2\sin{90}}{9.8}=23\ m\\ t=2\frac{15\cos{45}}{9.8}=2.2\ s\\ h=\frac{15^2\cos^2{45}}{2\cdot9.8}=5.7\ m\\v=15\frac{m}{s}$$

c)

$$R=\frac{15^2\sin{140}}{9.8}=14.8\ m\\ t=2\frac{15\cos{70}}{9.8}=1.0\ s\\ h=\frac{15^2\cos^2{70}}{2\cdot9.8}=1.3\ m\\v=15\frac{m}{s}$$

d)

$$R=24.2\ m\\ t=1.6\ s\\ h=15\ m\\v=22.8\frac{m}{s}$$

e)

$$R=26.2\ m\\ t=1.7\ s\\ h=15\ m\\v=22.8\frac{m}{s}$$

f)

$$R=33.3\ m\\ t=3.1\ s\\ h=15\ m\\v=22.8\frac{m}{s}$$

g)

$$R=19\ m\\ t=3.7\ s\\ h=25.1\ m\\v=22.8\frac{m}{s}$$