Question

two identical 15 kg balls each 25 cm on diameter are suspended by two 35 cm wires. The entire apparatus is suspended by a single 18 cm wire. Find the tension in each of the 3 wires

Answer 1

$T_1=T_2=T$

$T\sin\alpha=mg\to T=\frac{mg}{\sin\alpha}$

$\sin \alpha=\frac{\sqrt{0.35^2-0.125^2}}{0.35}=0.934$

$T=\frac{mg}{\sin\alpha}=\frac{15\cdot9.8}{0.934}\approx157\ (N)$ . Answer

$T_3=2mg=2\cdot15\cdot9.8=294\ (N)$ . Answer