two identical 15 kg balls each 25 cm on diameter are suspended by two 35 cm wires. The entire apparatus is suspended by a single 18 cm wire. Find the tension in each of the 3 wires
"T_1=T_2=T"
"T\\sin\\alpha=mg\\to T=\\frac{mg}{\\sin\\alpha}"
"\\sin \\alpha=\\frac{\\sqrt{0.35^2-0.125^2}}{0.35}=0.934"
"T=\\frac{mg}{\\sin\\alpha}=\\frac{15\\cdot9.8}{0.934}\\approx157\\ (N)" . Answer
"T_3=2mg=2\\cdot15\\cdot9.8=294\\ (N)" . Answer
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