Answer to Question #168086 in Physics for Boogie

Question

Jay pushed her 12.5 kg bed across the room with a force of 40 N over 11 m at an angle of 28 degrees. How much work is being done?

Answer 1

By the definition of the work done, we have:

$$W=Fdcos\theta=40\ N\cdot11\ m\cdot cos28^{\circ}=388.5\ J.$$