Answer to Question #168086 in Physics for Boogie

Question #168086

Jay pushed her 12.5 kg bed across the room with a force of 40 N over 11 m at an angle of 28 degrees. How much work is being done?

Expert's answer

By the definition of the work done, we have:

"W=Fdcos\\theta=40\\ N\\cdot11\\ m\\cdot cos28^{\\circ}=388.5\\ J."

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