Question

A capacitor with air between its plates is connected across a potential difference of 120.0V and stores 600.0 uC of charge. What is the capacitance of the capacitor? (C=Q/V)

Answer 1

We can find the capacitance of the capacitor as follows:

$$C=\dfrac{Q}{\Delta V}=\dfrac{600\cdot10^{-6}\ Q}{120\ V}=5\cdot10^{-6}\ F=5\ \mu F.$$