Question

A capacitor with air between its plates is connected across a potential difference of 120.0V and stores 600.0 μC of charge. What is the capacitance of the capacitor? (C = Q / ΔV )

Answer 1

$$C=\frac{Q}{\Delta V}\\C=\frac{600\cdot10^{-6}}{120}=5\cdot10^{-6}\ F$$