Question

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A potential difference of 10.0 volts exists between two points, A and B, within an electric field. What is the magnitude of charge that requires 2.0 × 10–2 Joule of work to move it from A to B? (V = W / q

Answer 1

Let's write the relationship between the electrical potential difference, work done and the amount of charge:

$$\Delta V=V_B-V_A=\dfrac{W}{q},$$ $$q=\dfrac{W}{\Delta V}=\dfrac{2.0\cdot10^{-2}\ J}{10\ V}=2\cdot10^{-3}\ C.$$

Answer:

$q=2\cdot10^{-3}\ C.$