Answer to Question #167219 in Physics for Renae

Question #167219

A toy truck of mass 10 kg

Expert's answer

The acceleration of centre of mass of the two is

"a_{cm}=\\frac{m_1a_1+m_2a_2}{m_1+m_2}\\\\a_{cm}=\\frac{20(10)+10(40)}{10+20}=20\\frac{m}{s^2}"

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