Question #166608

an airplane wishes to fly directly EAST at 900km/h. however a wind is blowing from 65 degrees south of east at 80 what is the planes heading? give magnitude and direction


1
Expert's answer
2021-02-25T11:24:00-0500
v=9002+8022(900)(80)cos65=869kmhv=\sqrt{900^2+80^2-2(900)(80)\cos{65}}=869\frac{km}{h}

θ=arcsin(80869sin65)=4.8° N of E\theta=\arcsin{\left(\frac{80}{869}\sin{65}\right)}=4.8\degree\text{ N of E}


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS