Question

The voltage induced in a 345-turns coil is 270 mV. What is the rate of change in flux?

Answer 1

$$\Epsilon=-N\dfrac{d\Phi_B}{dt},$$ $$\dfrac{d\Phi_B}{dt}=-\dfrac{\Epsilon}{N}=-\dfrac{270\cdot10^{-3}\ V}{345}=-7.83\cdot10^{-4}\ \dfrac{Tm^2}{s}.$$