Question

What is the absorbed dose when 3 mJ of energy is absorbed by a mass of 10 kg?

Answer 1

By definition, the absorbed dose is measure of the energy deposited in matter by ionizing radiation per unit mass:

$$D = \dfrac{E}{m}$$

where $E = 3mJ = 3\times 10^{-3}J$ is the total absorbed energy, and $m = 10kg$ is the mass. Thus, obtain:

$$D = \dfrac{3\times 10^{-3}J}{10kg} = 3\times 10^{-4}Gy$$

Answer. $3\times 10^{-4}Gy$.