Answer to Question #166040 in Physics for Scott

Question

A new conveyor system at the local packaging plan will utilize a motor-powered mechanical arm to exert an average force of 890 N to push large crates a distance of 12 meters in 22 seconds. Determine the power output required of such a motor.

Answer 1

The power of a motor

$$P=\frac{work\: done}{time}=\frac{W}{t}=\frac{Fd}{t}$$

$$P=\rm\frac{890\: N\times12\: m}{22\: s}=485\: W$$