Question #166037

A 75-kg man pushes a 10-kg cart along a 25-m corridor with a 1500-N force at an angle of 30O with the horizontal at a µ of 0.45.Find the work done.


1
Expert's answer
2021-02-23T10:02:38-0500

The work done by a man

W=FdcosθW=Fd\cos\theta=1500N×25m×cos30=32476J=32.5kJ=\rm 1500\: N\times 25\: m\times \cos 30^{\circ}=32476\: J=32.5\: kJ

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