Question #166030

A 4.0 kg block rests at the edge of a platform that is 20 m above level ground.  The block is launched horizontally with an initial velocity of 15 m/s. The time it would take to reach the ground is most nearly


1
Expert's answer
2021-02-23T10:02:45-0500
t=2hgt=2(20)9.8=2.0 st=\sqrt{\frac{2h}{g}}\\t=\sqrt{\frac{2(20)}{9.8}}=2.0\ s


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