Question #166007

Find the resultant and direction of 15N and 20N acting 75° with the horizontal



1
Expert's answer
2021-02-23T10:03:07-0500
R=152+202+2(15)(20)cos75=27.9 Nα=arctan20sin7515+20cos75=43.8°R=\sqrt{15^2+20^2+2(15)(20)\cos{75}}=27.9\ N\\\alpha=\arctan{\frac{20\sin{75}}{15+20\cos{75}}}=43.8\degree


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