Question #165983

The position of a body oscillating on a spring is given by x = A sin t, where A and v are constants with values A = 5 cm and  = 0.175 s-1. (a) Sketch x versus t for 0  t  36 s. (b) Measure the slope of your graph at t = 0 to find the velocity at this time. (c) Calculate the average velocity for a series of intervals beginning at t = 0 and ending at t = 6, 3, 2, 1, 0.5, and 0.25 s. (d) Compute dx/dt and find the velocity at time t = 0.


1
Expert's answer
2021-02-23T10:03:17-0500

a)


x=5sin0.175tx=5\sin{0.175t}


b)


v=0.875cmsv=0.875\frac{cm}{s}

c)


v1=0.440cmsv2=0.118cmsv3=0.053cmsv4=0.013cmsv5=0.003cmsv6=0.0008cmsv_1=-0.440\frac{cm}{s}\\v_2=-0.118\frac{cm}{s}\\v_3=-0.053\frac{cm}{s}\\ v_4=-0.013\frac{cm}{s}\\v_5=-0.003\frac{cm}{s}\\v_6=-0.0008\frac{cm}{s}\\

d)


v=0.875cmsv=0.875\frac{cm}{s}


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