Answer to Question #165931 in Physics for Jessica

Question

Length of brass if the linear expansivity is 1.20×10^–5 kelvin and temperature is 0°c

Answer 1

$$L=L_0(1+\alpha(T-T_0))\\ \alpha=1.2\cdot10^{-5}K^{-1}\\T_0=273.15\ K$$