Answer to Question #165673 in Physics for Khalid

Question

A gas with a constant pressure of 270 kPa does 36000 J of work as it expands. What is the change in the volume of the gas?

Answer 1

By the definition of the work done by the gas, we have:

$$W=P\Delta V ,$$ $$\Delta V=\dfrac{W}{P}=\dfrac{36000\ J}{270000\ Pa}=0.133\ m^3.$$