Question

How much work does thr force f =12.0n do on a particule as it moves from x=2.0m to x=7.5

Answer 1

The work done by the constant force $F$, making displacement $s$ is $A = F s = F (x_2 - x_1)$, where $x_2, x_1$ are the final and initial coordinates respectively.

Hence, $A = 12.0 N \cdot (7.5 m - 2.0 m) = 66 J$.