Question #165513
  1. A runner wants to run 10,000m in 30 minutes. After 27 minutes he has run 8,900m. For how long must he accelerates at 0.02 m/s2 and then maintain that final speed?
1
Expert's answer
2021-02-22T10:21:03-0500
tmax=(3027)60=180 sv=89002760=5.49mst_{max}=(30-27)60=180\ s\\v=\frac{8900}{27\cdot60}=5.49\frac{m}{s}

10000=8900+5.49t+0.5(0.02)t2t=156 s10000=8900+5.49t+0.5(0.02)t^2\\t=156\ s


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