Question #164651

The increase in the volume of 10cm³ of mercury when temperature rises by 100⁰c is 0.182cm³, what is the cubic expansivity of mercury


1
Expert's answer
2021-02-19T10:31:14-0500

By definition, the increase in volume will be:




ΔV=βV0ΔT\Delta V = \beta V_0\Delta T

where β\beta is the cubic expansivity, V0=10cm3V_0 = 10cm^3 is the initial volume, and ΔT=100°C\Delta T = 100\degree Cis the change in temperature. Since ΔV=0.182cm3\Delta V = 0.182cm^3, the cubic expansivity is:



β=ΔVV0ΔTβ=0.18210100=1.82×104°C1\beta = \dfrac{\Delta V}{V_0\Delta T}\\ \beta = \dfrac{0.182}{10\cdot 100} = 1.82\times 10^{-4}\degree C^{-1}

Answer. 1.82×104°C11.82\times 10^{-4}\degree C^{-1}.


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