Question #164589

An 8-in-diameter horizontal pipe is attached to a reservoir, as shown in Fig. 8-26. If the total head loss between the water surface in the reservoir and the water jet at the end of the pipe is 6.0 ft, what are the velocity and flow rate of the water being discharged from the pipe?


1
Expert's answer
2021-02-22T10:26:11-0500
v=2gh=2(9.8)(60.3048)=6.0msdVdt=Av=0.25πd2v=0.25π(80.0254)2(6)=0.19m3sv=\sqrt{2gh}=\sqrt{2(9.8)(6\cdot0.3048)}=6.0\frac{m}{s}\\ \frac{dV}{dt}=Av=0.25\pi d^2v\\=0.25\pi(8\cdot0.0254)^2(6)=0.19\frac{m^3}{s}


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