Answer to Question #163718 in Physics for Smayya Ruganyira

Question #163718

Explain why ambulances have the word ‘ambulance’ reversed on the front bonnet of the car?




If a stool 0.5 m high is placed 2 m in front of a plane mirror, how far behind the plane mirror will the image be and how high will the image be?




If Susan stands 3 m in front of a plane mirror, how far from Susan will her image be located?




A dental technician uses a small mirror that gives a magnification of 4.0 when it is held 0.60cm from a tooth. What is the radius of the curvature of the mirror?




An object 2 cm high is placed 4 cm from a convex mirror. If the focal length of the mirror is 4 cm, find the position and size of the image by means of a ray diagram. Is the image real or virtual? Calculate the magnification.


1
Expert's answer
2021-02-17T11:06:52-0500

Explain why ambulances have the word ‘ambulance’ reversed on the front bonnet of the car?

Because what the drivers see in their mirrors is reflected. If they see a reflection of a reversed word, they will read it the normal way.


If a stool 0.5 m high is placed 2 m in front of a plane mirror, how far behind the plane mirror will the image be and how high will the image be?

Plane mirrors do not distort: 2 m behind the mirror, 0.5 m high.


If Susan stands 3 m in front of a plane mirror, how far from Susan will her image be located?

The distance will be 6 m (distance of Susan to the mirror added to distance from the mirror to the reflection).


A dental technician uses a small mirror that gives a magnification of 4.0 when it is held 0.60cm from a tooth. What is the radius of the curvature of the mirror?

We know that

"m=\\frac{v}{u}=\\frac{-v}{-0.6}=4,\\\\\\space\\\\\nv=2.4\\text{ cm}.\\\\\\space\\\\\n\n\\frac 1f=\\frac1v+\\frac1u,\\\\\\space\\\\\n\\frac{1}{f}=\\frac{1}{2.4}+\\frac{1}{-0.6},\\\\\\space\\\\\nf=-0.8\\text{ cm}.\\\\\nR=2f=-1.6\\text{ cm}."

An object 2 cm high is placed 4 cm from a convex mirror. If the focal length of the mirror is 4 cm, find the position and size of the image by means of a ray diagram. Is the image real or virtual? Calculate the magnification.

Use https://ophysics.com/l10.html to build the ray diagram:


The magnification is -0.5, the image is upright and virtual.



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