Question

A body of mass 40kg is given an acceleration of 10ms on a horizontal ground for which coefficient of static friction =0.5. Calculate the force required to accelerate the body(take g=10ms)

Answer 1

Applying the Newton's Second Law of Motion, we get:

$$F-F_{fr}=ma,$$ $$F-\mu_smg=ma,$$ $$F=m(a+\mu_sg),$$ $$F=40\ kg\cdot(10\ \dfrac{m}{s^2}+0.5\cdot10\ \dfrac{m}{s^2})=600\ N.$$