Question

 Solve the problem and show the complete solution.

A uniform electric field E = 5000 N/C is passing through a flat square area A= 2m2 . Determine the electric flux. θ = 60o (the angle between the electric field direction and a line drawn perpendicular to the area)

Answer 1

The electric flux of the uniform field is given as follows:

$$\Phi = E_nA$$

where $E_n$ is the normal component of the electric field, and $A = 2m^2$ is the area. Since the angle between the electric field direction and a line drawn perpendicular to the area is $\theta = 60\degree$, the normal component of the field $E = 5000N/C$ is:

$$E_n = E\cos\theta$$

Finally, obtain:

$$\Phi = AE\cos\theta\\ \Phi = 2\cdot 5000\cdot \cos60\degree = 5000\space \dfrac{N\cdot m^2}{C}$$

Answer. $5000\space \dfrac{N\cdot m^2}{C}$.