Answer to Question #163412 in Physics for Johnny Tim

Question

Can you answer the questions below?

https://lh3.googleusercontent.com/-oAr6Anl2Ot8/YCayeUrceiI/AAAAAAAAlnI/DHg6y855j3cBi_vADz4OWv7Zw3zCVETywCK8BGAsYHg/s512/2021-02-12.png

Answer 1

a)

$$F\Delta t_1=m_1v\\667\cdot0.0038=0.023v\\v=110.2\frac{m}{s}$$

b)

$$(m_1+m_2)u=F\Delta t_1\\(0.023+1.4)u=667\cdot0.0038\\u=1.78\frac{m}{s}$$

c)

$$(0.023+1.4)1.78=F\cdot0.0075\\F_1=337.7\ N=0.506F$$

d)

$$F\Delta t_1=m_1v$$

$$m_1v=(m_1+m_2)u=F\Delta t_1$$

$$0.5(m_1+m_2)u^2=\mu (m_1+m_2)gd$$

$$d=\frac{F^2\Delta t_1^2}{2\mu g (m_1+m_2)^2}$$

$$d=\frac{(667\cdot0.0038)^2}{2(0.63)(9.8)(0.023+1.4)^2}=0.27\ m$$