Question #163412

Can you answer the questions below?


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1
Expert's answer
2021-02-15T17:39:38-0500

a)


FΔt1=m1v6670.0038=0.023vv=110.2msF\Delta t_1=m_1v\\667\cdot0.0038=0.023v\\v=110.2\frac{m}{s}

b)


(m1+m2)u=FΔt1(0.023+1.4)u=6670.0038u=1.78ms(m_1+m_2)u=F\Delta t_1\\(0.023+1.4)u=667\cdot0.0038\\u=1.78\frac{m}{s}

c)


(0.023+1.4)1.78=F0.0075F1=337.7 N=0.506F(0.023+1.4)1.78=F\cdot0.0075\\F_1=337.7\ N=0.506F

d)


FΔt1=m1vF\Delta t_1=m_1v

m1v=(m1+m2)u=FΔt1m_1v=(m_1+m_2)u=F\Delta t_1

0.5(m1+m2)u2=μ(m1+m2)gd0.5(m_1+m_2)u^2=\mu (m_1+m_2)gd

d=F2Δt122μg(m1+m2)2d=\frac{F^2\Delta t_1^2}{2\mu g (m_1+m_2)^2}

d=(6670.0038)22(0.63)(9.8)(0.023+1.4)2=0.27 md=\frac{(667\cdot0.0038)^2}{2(0.63)(9.8)(0.023+1.4)^2}=0.27\ m


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