Question #163243

A fire truck travels down the highway at the speed of 120 km/h. Its siren has an emitting sounds at a frequency of 4 x 10⁴ Hz. 


a) What is heard by the passenger in the car traveling at 100 km/h in opposite direction, when the sound velocity is 340 m/s?



b) What will happen in the frequency heard if the direction of the two vehicles will be approaching each other?


Expert's answer

a) We can find the frequency from the Doppler Shift formula:


fo=fs(vv0v+vs),f_o=f_s(\dfrac{v-v_0}{v+v_s}),fo=4104 Hz(340 ms27.77 ms340 ms+33.33 ms)=3.34104 Hz.f_o=4\cdot10^4\ Hz\cdot(\dfrac{340\ \dfrac{m}{s}-27.77\ \dfrac{m}{s}}{340\ \dfrac{m}{s}+33.33\ \dfrac{m}{s}})=3.34\cdot10^4\ Hz.

(b) We can find the frequency from the Doppler Shift formula:


fo=fs(v+v0vvs),f_o=f_s(\dfrac{v+v_0}{v-v_s}),fo=4104 Hz(340 ms+27.77 ms340 ms33.33 ms)=4.8104 Hz.f_o=4\cdot10^4\ Hz\cdot(\dfrac{340\ \dfrac{m}{s}+27.77\ \dfrac{m}{s}}{340\ \dfrac{m}{s}-33.33\ \dfrac{m}{s}})=4.8\cdot10^4\ Hz.
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