Answer to Question #162856 in Physics for Marie

Question

Three charges lie in the plane in a vacuum as shown. The distance between q1 and q2 is 5.0 cm while the distance between q2 and q3 is 7.5cm. If q1= +3.0 nC, q2= -1.5nC and q3= +2.0 nC, find the magnitude and direction of the net electrostatic force on q2.

Answer 1

Assume that the charges are placed on one line. So, we have

$F_1=k\frac{q_1q_2}{r_1^2}=9\cdot10^9\cdot \frac{3\cdot10^{-9}\cdot1.5\cdot10^{-9}}{0.05^2}=0.0000162(N)$

$F_1=k\frac{q_3q_2}{r_2^2}=9\cdot10^9\cdot \frac{2\cdot10^{-9}\cdot1.5\cdot10^{-9}}{0.075^2}=0.00000048(N)$

$F=0.00000048-0.0000162=-0.00001572(N)$ to the charge $q_1$ . Answer