Answer to Question #162733 in Physics for kyle

Question

Make your own problem.One problem calculating the period and the frequency of simple pendulum and one in physical pendulum.show your comple solutions to the problem.

Answer 1

1)

$$f=\frac{1}{2\pi}\sqrt{\frac{g}{l}}\\f=\frac{1}{2\pi}\sqrt{\frac{9.8}{1}}=0.498\ Hz\\T=2\pi\sqrt{\frac{1}{9.8}}=2.01\ s$$

2)

$$f=\frac{1}{2\pi}\sqrt{\frac{mgh}{I}}\\f=\frac{1}{2\pi}\sqrt{\frac{(1)(1)9.8}{1}}=0.498\ Hz\\T=2\pi\sqrt{\frac{1}{(1)(1)9.8}}=2.01\ s$$