Question #162591

A 5 kg block lies on a rough horizontal surface. The coefficient of static friction μs = 0.22. It is connected to another 3 kg block by a string that passes a frictionless pulley as shown in the figure below. 

a. Find the unbalanced force, b. Find the acceleration of the blocks, and c. Find the tension T in the string



1
Expert's answer
2021-02-10T08:35:11-0500

mgT=mamg-T=ma

TμMg=MaT-\mu Mg=Ma


3gT=3a3g-T=3a

T0.225g=5aT-0.22\cdot5\cdot g=5a


T=3g3aT=3g-3a


3g3a0.225g=aa=(3g0.225g)/4=3g-3a-0.22\cdot5\cdot g=a \to a=(3g-0.22\cdot5\cdot g)/4=


=(39.80.2259.8)/4=4.67 (m/s2)=(3\cdot9.8-0.22\cdot5\cdot 9.8)/4=4.67\ (m/s^2) . Answer


T=39.834.67=15.4 (N)T=3\cdot9.8-3\cdot4.67=15.4\ (N) . Answer


Funb1=15.40.2259.8=4.62(N)F_{unb1}=15.4-0.22\cdot 5\cdot9.8=4.62(N)


Funb2=39.815.4=14(N)F_{unb2}=3\cdot9.8-15.4=14(N) . Answer






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