The rod stays in balance. What is the length AB of it? F1 = 10N, F2 = 5N, AO = 1m, OB = X, AB = 1 + x
M1=M2→10⋅1=x⋅5→x=2 (m)M_1=M_2\to 10\cdot1=x\cdot5\to x=2\ (m)M1=M2→10⋅1=x⋅5→x=2 (m)
AB=1+2=3 (m)AB=1+2=3\ (m)AB=1+2=3 (m) . Answer
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