Question #162415

The rod in the figure is in balance. What will be the size of weight P1? P2 = 50N, d1 = 15cm, d2 = 30cm


1
Expert's answer
2021-02-15T17:42:56-0500
P1d1=P2d2,P_1d_1=P_2d_2,P1=P2d2d1=50 N⋅0.3 m0.15 m=100 N.P_1=\dfrac{P_2d_2}{d_1}=\dfrac{50\ N\cdot0.3\ m}{0.15\ m}=100\ N.

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