Question

TASK 5

The force F is applied to the end of a homogeneous board with length I and mass 5 kg. The angle formed by the direction of the force with the board is 30⁰. The other end of the board is fixed to the wall. What will be the value of this force, so that the board stays in the horizontal position?

Answer 1

$$0.5lmg=Fl\sin{30}\\F=mg=(5)(9.8)=49\ N$$