Question #162003

A 1000cm3 vessel is filled with two liquids (l1,l2) of relative densities l1=0.75 and l2=1.85.

If the relative density of the mixture was found to be 1.5, what volume of each liquid enters the mixture.

Assume there is no volume change when liquids mix


1
Expert's answer
2021-02-08T18:39:04-0500

We have two masses in the vessel. Assume one takes x mL and the other V-x. Then the mass of the mixture in the vessel would be


M=xρ1+(Vx)ρ2.M=x\rho_1+(V-x)\rho_2.

We know the relative density of the mixture:


ρ=MV=xρ1+(Vx)ρ2V.\rho=\frac{M}{V}=\frac{x\rho_1+(V-x)\rho_2}{V}.

Find x:


x=V(ρ2ρ)ρ2ρ1=1000(1.851.5)1.850.75=318 cm3.x=V\frac{(\rho_2-\rho )}{\rho_2 -\rho_1}=1000\frac{(1.85-1.5)}{1.85 -0.75}=318\text{ cm}^3.

Thus, we have 318 mL of liquid 1 and 682 mL of liquid 2.


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